Leveraging TypeScript Generics for Type Reusability

Is there a way to extend the generic types defined in the type T to a function without duplicating code? Can we reuse generics between types and functions?

type T<FormType extends 'edit' | 'create' = 'create', RecordType extends Record = Record> = {
   type: FormType,
   record: RecordType
}

const func = <FormType extends 'edit' | 'create' = 'create', RecordType extends Record = Record>(props: T<FormType, RecordType>) => ...

How can we expand the 

<FormType extends 'edit' | 'create' = 'create', RecordType extends Record = Record>
from type generics to function generics without having to duplicate the code?

typescriptgenericstypescript-typingstypescript-generics

Answer №1

One approach that can be useful is simplifying it to a single Base type:

type CommonType = {
  form: 'edit' | 'create'
  dataType: Data
}

type Base = {
  form: 'edit';
  dataType: Data
}

type CustomType<B extends CommonType = Base> = {
   kind: FormKind,
   data: DataType
}

const customFunction = <B extends CommonType = Base>(props: CustomType<B['form'], B['data']>) => ...

This method significantly reduces verbosity, especially with an increasing number of generics.

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