Loop through a collection of elements of a certain kind and selectively transfer only certain items to a different collection of a different kind

Question

Loop through a collection of elements of a certain kind and selectively transfer only certain items to a different collection of a different kind

When working with typescript, I am faced with the challenge of dealing with two arrays:

interface IFirst{
    name: string;
    age: number
}

interface ISecond {
    nickName: string;
    lastName: string;
}   

myFirstArray: IFirst[];
mySecondArray: ISecond[];

myFirstArray = [
    {name: 'tim', age: 20},
    {name: 'jim', age: 30}
]

I am trying to figure out a way to loop through myFirstArray and assign all names as nicknames in mySecondArray. Is there a method to achieve this functionality?

this.myFirstArray.forEach((element: IFirst) => {
        this.mySecondArray.push({nickName = element.name});
      })

arrays angular typescript

Answer 1

Answer №1

If you only want to set a nickname, you can make the lastName field optional in the ISecond interface by using lastName?: string. The updated interface will look like this:

interface ISecond {
  nickName: string;
  lastName?: string;
}

To assign the nickname value from each element of myFirstArray to mySecondArray, you can utilize the this.myFirstArray.map() method. Here's how you can do it:

this.mySecondArray = this.myFirstArray.map((element: IFirst) => {
  return { nickName: element.name };
});

console.log("this.mySecondArray ", this.mySecondArray);

Check out the working code on Stackblitz... (View console for output).

Answer 2

If you only want to set a nickname, you can make the lastName field optional in the ISecond interface by using lastName?: string. The updated interface will look like this:

interface ISecond {
  nickName: string;
  lastName?: string;
}

To assign the nickname value from each element of myFirstArray to mySecondArray, you can utilize the this.myFirstArray.map() method. Here's how you can do it:

this.mySecondArray = this.myFirstArray.map((element: IFirst) => {
  return { nickName: element.name };
});

console.log("this.mySecondArray ", this.mySecondArray);

Check out the working code on Stackblitz... (View console for output).

Answer 3

Answer №2

In this scenario, mySecondArray is defined as an array of type ISecond. Therefore, when assigning values to it, both properties of the object must be included.

For example -

this.myFirstArray.map((element: IFirst) => {
  this.mySecondArray.push({nickName = element.name, lastName: ''});
})

Answer 4

In this scenario, mySecondArray is defined as an array of type ISecond. Therefore, when assigning values to it, both properties of the object must be included.

For example -

this.myFirstArray.map((element: IFirst) => {
  this.mySecondArray.push({nickName = element.name, lastName: ''});
})

Answer 5

Answer №3

Utilize the map function to transform your array:

this.peopleList = [
    {name: 'Alice', age: 25},
    {name: 'Bob', age: 35}
];
this.modifiedPeopleList = this.peopleList.map(({name, age})=> <IModified><any>{ 
    fullName: name,
    yearsOld: age
    });
console.log(this.modifiedPeopleList);

Answer 6

Utilize the map function to transform your array:

this.peopleList = [
    {name: 'Alice', age: 25},
    {name: 'Bob', age: 35}
];
this.modifiedPeopleList = this.peopleList.map(({name, age})=> <IModified><any>{ 
    fullName: name,
    yearsOld: age
    });
console.log(this.modifiedPeopleList);

Answer 7

Answer №4

Make sure to properly set up your second array:

friends: IFriend[] = [];

Once initialized, populate it by iterating through the first array:

this.users.forEach((user: IUser) => {
    this.friends.push({username: user.name, lastName: ''});
})

Answer 8

Make sure to properly set up your second array:

friends: IFriend[] = [];

Once initialized, populate it by iterating through the first array:

this.users.forEach((user: IUser) => {
    this.friends.push({username: user.name, lastName: ''});
})

Loop through a collection of elements of a certain kind and selectively transfer only certain items to a different collection of a different kind

Answer №1

Answer №2

Answer №3

Answer №4

Similar questions

What is the best way to dynamically import two css frameworks in React?

The import of type cannot be done within paths in tsconfig

Combining arrays in JSON with the power of Groovy 2.4

Guide on incorporating a range object into a VBA function to produce an array output

Using type definitions in non-TS files with VSCode: A beginner's guide

The specific property 'splice' cannot be found within type 'T'

Including elements into an array encoded in JSON

What is the best way to send multiple parameters to @Directives or @Components in Angular using TypeScript?

What is the best way to organize values within an array in PHP?

The JSX component cannot be named 'Stack.Navigator' or used as such

Learning how to smoothly navigate to the top of a page when changing routes in Angular using provideRouter

Angular - Reacting to dynamically rendered content post-navigation

Using Ionic2 to connect with PHP server APIs

Angular Error TS2554: Received x arguments instead of the expected 0 on piped operators

Having trouble getting the installed datejs typings to work properly

Encountered an issue when attempting to send data using this.http.post in Angular from the client's perspective

Angular2 app fails to update after emitting an event

Retrieve predefined values from a TypeScript controller in Stimulus using the default Symfony configurations

Filling a data entry with simultaneous commitments

Looking for the closest latitude and longitude values in a multi-dimensional array