Mapped types in TypeScript are utilized to create an object representation that includes optional Observables with keys mapped as string literals

I am in need of a customized type to depict an object where the properties can optionally be RxJS Observables.

The most straightforward approach to accomplish this is by using the following type:

type OptionalObservables<T> = {
   [K in keyof T]: T[K] | Observable<T[K]>
}

You can use it as follows:

const animal: OptionalObservables<Animal> = {

    species: 'dog',
    noise: of('bark')     // RxJS Observable that satisfies Observable<string>
}
  

(I have a separate function for parsing an object and subscribing to observables. However, this query does not focus on the RxJS aspect.)

But... I typically favor utilizing the $ suffix convention specifically for observables. Thus, I prefer adding a $ at the end when selecting an observable key. This kind of manipulation is feasible with Key Remapping.

{
    species: 'dog',
    noise$: of('bark')  
}

Aligning everything together turned out to be more challenging than expected!

The final type required for

OptionalObservables<{ species: string, noise: string }>
would resemble:

// species either as a string or observable
({ species: string } | { species$: Observable<string> }) &

// noise either as a string or observable
({ noise: string } | { noise$: Observable<string> })

(Each property K of T must be mandatory and could be of type T[K] or Observable<T[K]>).


The closest foundational concept I reached was something like this:

type OptionalObservables<T> = 
{
   [K in keyof T]: K extends string ? 

                   // original property name and type
                   { [P in K]: T[K] } 

                   |

                   // OR original property name with $ suffix and Observable type
                   { [P in `${K}\$`]: Observable<T[K]> }  
                   : never
}

This introduces an added level of 'nesting' (yet meets my criteria) resulting in:

{
    species: {
        species: "cat" | "dog";
    } | 
    {
        species$: Observable<"cat" | "dog">;
    };

    noise: {
        noise: "bark" | "meow";
    } | 
    {
        noise$: Observable<"bark" | "meow">;
    };
}

I had hoped that reaching this point would enable me to utilize something like Unionize to extract the values and merge them back without the extra nesting. So far, I've only succeeded in making all properties required or all optional!

If there's a technique I'm overlooking or if it's unattainable - I am eager to make this work.

An alternative approach might involve validating the structure's compatibility through a method rather than solely relying on a mapped type.

Answer №1

Your request is quite unique, but not impossible to achieve.

We may need to resort to some mysterious dark magic in TypeScript, but as you are aware, using such powers should not be taken lightly. 😀

Check out Playground Link

Code Fragment

type Observable<T> = {value: T}

declare function of<T>(val: T): Observable<T>

type Animal = {
    species: 'species'
    noise: 'noise'
}

type Unwrap<T> = T extends [any] ? T[0] : T

// Further code continues...

Recommended Steps

  1. Start by extracting the keys of the specified type
  2. Map each key type to the corresponding distributed union type
  3. Encapsulate each part as a tuple to prevent alteration in subsequent steps
  4. Transform the union type into an intersection type
  5. Finally, unwrap the tuple type to find the solution

Identified Issue

Despite defining the correct type, TypeScript currently does not support intersections of union types. This allows unexpected scenarios like the one depicted below:

const test: OOA = {
    species: 'species',
    noise$: of('noise'),
    noise: 'noise',
}

An open issue regarding this limitation might exist within the TypeScript community and could potentially be addressed in future updates.

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