Mapping type property names in Typescript for substitution

I am working on a function that accepts two objects as parameters: one representing a model and the other representing a mapping. The function then returns an object with two properties: one showing the base model and the other displaying the model with each property wrapped in another type. The key-value pairs of the returned object are determined by the mapping provided, which will always follow this structure:

type Mapping<Model> = {
    foo: string,
    bar: string
}
function fooBar<M extends object, B extends Mapping>(model: M, mapping: B) {
    return {
        [mapping.foo]: model,
        [mapping.bar]: recursiveWrap(model) //this function would go through the model and wrap each property
    }
}

For example, calling this function like so:

fooBar({ message: 'hello' }, { foo: 'thing', bar: 'thing$' })

should result in a type similar to this:

type MyType = {
    thing: { message: string },
    thing$: WrappedType<{ message: string  }>
}

However, I am struggling to substitute property names from an object while maintaining proper type checking.

I tried following this question, but it led to the returned properties having a union type of

{ message: string } | WrappedType<{ message: string }>
. Is there a way to achieve this without resulting in a union type?

Answer №1

It may seem improbable at the moment (June 2021), but there is a chance for it to become feasible in the upcoming years.

Refer to:

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