Match a unique key in Typescript to ensure the same value for two distinct generic objects

There is a peculiar occurrence in TypeScript that I cannot comprehend.

The desired outcome is to have a function structured like this:

function getDbRowFromRow<T, Key extends keyof T, R extends Pick<T, Key>>(
  dbRow: T[],
  key: Key,
  row: R)
{
  const map = new Map<T[Key], T>(dbRows.map(r => [r[key], r]));

  // an error pops up at the key in this line
  map.get(row[key]);
}

https://www.typescriptlang.org/play?#code/GYVwdgxgLglg9mABAcwKZQCICMBKcDuAYgE5wC2e+APACoA0iA0qgJ6KoAeUqYAJgM6IA1qzjBE9RDnZceAxAAUYEIbQbMWAPk0AKAFCJEvXAX4AuCQG0AunQPDWFjXcOl8FnAEo9Ab3sQEfihEMgBDAAdEAF5EMFR8RABZCNpLDVsJXWNKfgA6MPCdYmjNREtiSxEWDOJrT08Abj17AHoWxCgAC1QHNi63QS6eqBZwntRiUmLu4lR7Aty0KCKCStY6poBfIA

This particular error message is displayed:

Argument of type 'R[Key]' is not assignable to parameter of type 'T[Key]'.
Type 'R' is not assignable to type 'T'.
'T' could be instantiated with an arbitrary type which could be unrelated to 'R'.

It puzzles me where something might be wrong, as it should be evident that if R extends Pick<T, Key>, then that aspect of the two generic objects must be identical.

Moreover, even attempting to as T[Key] on the row results in the usual insistence to first cast to unknown. It appears that the types are not perceived to be remotely interconnected.

Hence, what am I overlooking? Is there a method by which I could genuinely breach that type restriction, or is this simply a peculiar TypeScript idiosyncrasy?

If necessary, I will share the actual dilemma that needs resolving. Initially, I believed that a condensed example would provide better clarity.

Answer №1

function retrieveDbRow<T, Key extends keyof T> (
  databaseRows: T[],
  identifier: Key,
  targetRow: Pick<T, Key>) 
{
  const rowMap /* : Map<T[Key], T> */ = new Map(databaseRows.map(r => [r[identifier], r]));
  rowMap.get(targetRow[identifier]);
}

Answer №2

The TypeScript compiler struggles with performing complex analysis on combinations of generic type parameters, their constraints, and various other types like mapped and indexed access types. While it can handle some aspects of this, there are limitations to its capability as discussed in microsoft/TypeScript#28884.

When dealing with R extends Pick<T, K>, we want the compiler to recognize that (Pick<T, K> & U)[K] should be assignable to

T[K]</code. This seems logical, yet the compiler fails to acknowledge it due to the fact that <code>R
is considered a subtype of Pick<T, K>, introducing confusion.

To address this issue, one workaround involves widening a value of type R to a type

Pick<T, K></code before indexing into it:</p>
<pre><code>function getDbRowFromRow<T, K extends keyof T, R extends Pick<T, K>>(
  dbRows: T[], key: K, row: R) {
  const map = new Map<T[K], T>(dbRows.map(r => [r[key], r]));
  const r: Pick<T, K> = row; // okay
  map.get(r[key]); // okay
}

Playground link to code

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