I'm currently attempting to calculate the Shannon entropy in typescript:
Here's my current code:
val =[0.5035203893575573, 0.4964796106424427]
shannonEntropy(val){
let temp, temp2;
temp = -(val[0] * Math.log(val[0]))
temp2 = -(val[1] * Math.log(val[1]))
return temp + temp2;
}
It's giving me a result of 0.693122394072697, but it should be 0.999964
Can anyone point out what I might be doing incorrectly?
It appears that your issue lies in the necessity to utilize the base 2 logarithm instead of the natural logarithm. Fortunately, JavaScript since ES2015 includes a built-in function, Math.log2(), for this purpose:
const val =[0.5035203893575573, 0.4964796106424427]
const shannonEntropy = (val: number[]) =>
val.map(v => -v * Math.log2(v)).reduce((x, y) => x + y, 0);
console.log(shannonEntropy(val)); // 0.9999642406577658
If you prefer to maintain ES5 compatibility, you can still achieve the desired outcome by using the natural log and multiplying the result by Math.LOG2E:
const val =[0.5035203893575573, 0.4964796106424427]
const shannonEntropy = (val: number[]) =>
val.map(v => -v * Math.log(v)).reduce((x, y) => x + y, 0)*Math.LOG2E;
console.log(shannonEntropy(val)); // 0.9999642406577659
As you can observe, both approaches yield similar results (with any discrepancies attributed to numerical precision issues).
Trust this clarifies the matter; best of luck with your task!
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