Modify the ngb-timepicker formatting to output a string instead of an object

I am currently working on modifying ngb-timepicker so that it returns a string instead of an object. Right now, it is returning the following format:

{
  "hour": 13,
  "minute": 30
}

However, I want it to return in this format:

"13:30"

This is the HTML code I have used:

<div class="calendar"> <ngb-datepicker #dp 
[(ngModel)]="model"></ngb-datepicker>

<ngb-timepicker [(ngModel)]="time"></ngb-timepicker>

For the datepicker, I was able to convert the object into a string using the following method:

 constructor(private dateFormatter: NgbDateParserFormatter) {
const string_date = this.dateFormatter.format(this.model);
}

Is there a similar NgbDateParserFormatter function that can be used for time?

Answer №1

If you find yourself needing to go beyond setting a data-bound property with the [(ngModel)] syntax, consider using the expanded form instead. While the property binding [ngModel] handles updating the input DOM element, the event binding (ngModelChange) notifies external sources of any changes in the DOM.

Here's an example:

<ngb-timepicker [(ngModel)]="time" (ngModelChange)="onTimeChange($event)"></ngb-timepicker>
    <hr>
    <pre>{{newTime}}</pre>

In the Component file:

export class AppComponent  {
  name = 'Angular 6';
  public newTime:string='13:30';
  time = {hour: 13, minute: 30};
  
  onTimeChange(value:{hour:string,minute:string})
  {
     console.log(value)
     this.newTime=`${value.hour}:${value.minute}`;
  }
}

Check out the Live Demo for more details.

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