Modifying the return type of an observable using the map operator

I have been investigating how to modify the return type of an Observable.

My current framework is Angular 5.

Let's take a look at this example:

public fetchButterflyData(): Observable<Butterfly[]> {
    return http.get<Larva[]>('url').pipe(
        map( larva => new Butterfly(larva.dna))
    );
}

This code is triggering an ERROR because the compiler expects the larva object to be a Butterfly due to the return value, resulting in the following error:

"error TS2339: Property 'id' does not exist on type 'Butterfly[]'."

It appears that TypeScript does not permit type alterations within the observable. However, if you know of a way around this, I am open to suggestions.

Thank you for your interest in my query.

Answer №1

It appears that the solution provided has obscured a larger issue and potentially a misunderstanding of how the map function functions in rxjs.

In traditional Javascript, the map() method directly manipulates an array by executing a function for each item within it. For example, [1,2,3].map(x => x + 1) results in a new array with transformed items.

Contrastingly, in rxjs, the map() operates differently from Array's map. Despite sharing the same name, the rxjs version works on single values within a stream rather than arrays.

RXJS deals with streams, which you already know! Suppose you have a stream of larvae (which could be either terrifying or adorable!). However, using http.get, you actually receive a stream with only one value - the complete response from your http call.

The original code snippet is annotated below:

  public getButterfly(): Observable<Butterfly[]> {
   return http.get<Larva[]>('url').pipe(
       map( larva => {

           // Don't confuse this 'map' with the standard javascript map
           // Here, larva is likely an ARRAY returned from the HTTP call
           // Attempting to access larva.dna will result in 'undefined'
           // As dna is not a property of a javascript array
           // Hence, returning a butterfly OBJECT with undefined DNA

           return new Butterfly(larva.dna);
       })
   );
}

To address this issue, consider the following revised implementation:

public getButterflies() {
    return http.get<Larva[]>('url').pipe(
        map( larvae => larvae.map(larva => new Butterfly(larva.dna)))
    );
}

This updated code snippet achieves the following:

  • You receive an array (larvae) from the http call, specified as Larva[]
  • The standard javascript map function is applied to each item in the array to create a butterfly for each larva
  • The new array of butterflies replaces the original array in the stream
  • Note: The output type is inferred as Butterfly[]

Providing <Larva, Butterfly> informs the compiler without altering the behavior. Additionally, specifying output types aids in identifying errors within the pipe.

Consider using

tap(x => console.log('Message', x)
within the pipe to log values at different stages:

public getButterflies() {
    return http.get<Larva[]>('url').pipe(
        tap( x => console.log('Before map', x) ),
        map( larvae => larvae.map(larva => new Butterfly(larva.dna)),
        tap( x => console.log('After map', x) )
    ));
}

Remember, "tap" allows you to peek inside the pipeline, just like a water tap lets you see what's flowing through a pipe!

Answer №2

The map operator's type definitions are outlined below:

export declare function map<T, R>(
  project: (value: T, index: number
) => R, thisArg?: any): OperatorFunction<T, R>;

In the usage of the map operator, you have the ability to specify generic types. For instance, in your scenario, the T value represents the Butterfly and the R value represents the Larva.

public getButterfly(): Observable<Butterfly[]> {
  return http.get<Larva[]>('url').pipe(
    map<Larva, Butterfly>(larva => new Butterfly(larva.dna))
  );
}

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