Move all the attributes from one object stored in an array to another object within the same array using JavaScript or TypeScript

Question

Move all the attributes from one object stored in an array to another object within the same array using JavaScript or TypeScript

Is there a more efficient way to copy or move properties from one object within an array to another object? I've devised a simple logic that works, but I'm confident there must be a better approach. Can anyone offer some advice?

var first =  [
    {
        "AGREE_EFF_DATE__0": "02-Aug-2018",
        "AGREE_TERM_DATE__0": "30-Apr-2021",
        "AGREE_IND__0": "P1",
        "P_DBAR_IND__0": "N",
        "AGREE_EFF_DATE__1": "01-May-2021",
        "AGREE_TERM_DATE__1": null,
        "AGREE_IND__1": "NP",
        "P_DBAR_IND__1": "N",
        "PROVIDER_SPECIALITY__0": "PSYCHOLOGY, CLINICAL",
        "PROVIDER_SPECIALITY_CODE__0": "CK"
    }
];
var second = [
    {
        "STATUS": "ACTIVE",
        "MEDICARE_NUMBER" : 12345
    }
];

for(let i = 0; i < second.length; i++) {
    
    var first_keys = Object.keys(first[i]);
    var first_values = Object.values(first[i]);
    
    for(let j = 0; j < first_keys.length; j++) {
        second[i][first_keys[j]] = first_values[j];
    }
}


console.log(second);

//Output-
[
  {
    STATUS: 'ACTIVE',
    MEDICARE_NUMBER: 12345,
    AGREE_EFF_DATE__0: '02-Aug-2018',
    AGREE_TERM_DATE__0: '30-Apr-2021',
    AGREE_IND__0: 'P1',
    P_DBAR_IND__0: 'N',
    AGREE_EFF_DATE__1: '01-May-2021',
    AGREE_TERM_DATE__1: null,
    AGREE_IND__1: 'NP',
    P_DBAR_IND__1: 'N',
    PROVIDER_SPECIALITY__0: 'PSYCHOLOGY, CLINICAL',
    PROVIDER_SPECIALITY_CODE__0: 'CK'
  }
]

javascript arrays typescript copy

Answer 1

Answer №1

It is generally recommended to use iteration methods like arr.map(), arr.forEach(), or arr.reduce() over manually indexed loops.

An efficient way to merge objects is by using object spread functionality.

Combining these techniques, you can simplify the logic to:

const result = first.map((firstObj, i) => ({ ...firstObj, ...second[i] }))

In this approach, we are iterating over each element of the 'first' array using map() and creating a new array based on the function's result, which merges corresponding elements from the 'second' array.

The final step involves expanding both objects into a new object to generate the desired result.

var first =  [
    { a: 1, b: 2 },
    { a: 4, b: 5 },
];
var second = [
    { c: 3 },
    { c: 6 },
];

const result = first.map((firstObj, i) => ({ ...firstObj, ...second[i] }))

console.log(result)

This code snippet is also valid in TypeScript.

NOTE: One key distinction between my implementation and yours is that your code modifies the objects in 'second', whereas mine creates new objects without altering the original contents of 'second'.

Choosing between the two approaches depends on how the output is utilized and how data flows within your application.

Answer 2

It is generally recommended to use iteration methods like arr.map(), arr.forEach(), or arr.reduce() over manually indexed loops.

An efficient way to merge objects is by using object spread functionality.

Combining these techniques, you can simplify the logic to:

const result = first.map((firstObj, i) => ({ ...firstObj, ...second[i] }))

In this approach, we are iterating over each element of the 'first' array using map() and creating a new array based on the function's result, which merges corresponding elements from the 'second' array.

The final step involves expanding both objects into a new object to generate the desired result.

var first =  [
    { a: 1, b: 2 },
    { a: 4, b: 5 },
];
var second = [
    { c: 3 },
    { c: 6 },
];

const result = first.map((firstObj, i) => ({ ...firstObj, ...second[i] }))

console.log(result)

This code snippet is also valid in TypeScript.

NOTE: One key distinction between my implementation and yours is that your code modifies the objects in 'second', whereas mine creates new objects without altering the original contents of 'second'.

Choosing between the two approaches depends on how the output is utilized and how data flows within your application.

Answer 3

Answer №2

When working with iteration, it's important to be cautious as the number of elements in the first and second arrays may differ. One possible approach to address this issue is outlined below:

const firstArr = [
    {
        "AGREE_EFF_DATE__0": "02-Aug-2018",
        "AGREE_TERM_DATE__0": "30-Apr-2021",
        "AGREE_IND__0": "P1",
        "P_DBAR_IND__0": "N",
        "AGREE_EFF_DATE__1": "01-May-2021",
        "AGREE_TERM_DATE__1": null,
        "AGREE_IND__1": "NP",
        "P_DBAR_IND__1": "N",
        "PROVIDER_SPECIALITY__0": "PSYCHOLOGY, CLINICAL",
        "PROVIDER_SPECIALITY_CODE__0": "CK"
    }
];
const secondArr = [
    {
        "STATUS": "ACTIVE",
        "MEDICARE_NUMBER": 12345
    }
];

console.log(mergeArrays(firstArr, secondArr));

function mergeArrays(arr1, arr2) {
    const resultArr = [];
    const minLen = arr1.length < arr2.length ? arr1.length : arr2.length;

    for (let i = 0; i < minLen; i++) {
        resultArr.push({...arr1[i], ...arr2[i]});
    }

    return resultArr;
}

Answer 4

When working with iteration, it's important to be cautious as the number of elements in the first and second arrays may differ. One possible approach to address this issue is outlined below:

const firstArr = [
    {
        "AGREE_EFF_DATE__0": "02-Aug-2018",
        "AGREE_TERM_DATE__0": "30-Apr-2021",
        "AGREE_IND__0": "P1",
        "P_DBAR_IND__0": "N",
        "AGREE_EFF_DATE__1": "01-May-2021",
        "AGREE_TERM_DATE__1": null,
        "AGREE_IND__1": "NP",
        "P_DBAR_IND__1": "N",
        "PROVIDER_SPECIALITY__0": "PSYCHOLOGY, CLINICAL",
        "PROVIDER_SPECIALITY_CODE__0": "CK"
    }
];
const secondArr = [
    {
        "STATUS": "ACTIVE",
        "MEDICARE_NUMBER": 12345
    }
];

console.log(mergeArrays(firstArr, secondArr));

function mergeArrays(arr1, arr2) {
    const resultArr = [];
    const minLen = arr1.length < arr2.length ? arr1.length : arr2.length;

    for (let i = 0; i < minLen; i++) {
        resultArr.push({...arr1[i], ...arr2[i]});
    }

    return resultArr;
}

Move all the attributes from one object stored in an array to another object within the same array using JavaScript or TypeScript

Answer №1

Answer №2

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