Muting the unused variable alert in JavaScript

Whenever I run my typescript compiler, it always gives me errors about unused variables. In C programming, I would prevent this using the following method:

void foo(int bar)
{
    (void)bar;
}

Is there a similar workaround in JavaScript?

Answer №1

When working with the TSConfig file, you have the option to set

"no-unused-variable": true
to prevent it from flagging any unused variables within the entire project.

If you only want TypeScript to ignore a specific unused variable, you can prefix the variable name with an underscore like this:

function example(_variable:number) {
  return 0;
}

Answer №2

An unconventional yet effective approach is to utilize the variable in a creative way.

Although not well-versed in Typescript, a method to suppress warnings in C is demonstrated below:

void foo()
{
    int dummy=42;
    int x=dummy;
    dummy = x;
}

A similar technique could potentially be applied.

Alternatively, as suggested by Luke_ in the comments, prefixing the variable name with _ may also work.

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