"Observables in RxJs: Climbing the Stairs of

Previously, I utilized Promise with async/await syntax in my Typescript code like this:

const fooData = await AsyncFooData();
const barData = await AsyncBarData();

... perform actions using fooData and barData

However, when using RxJs Observable<T>, the structure changes to something like:

AsyncFooData().subscribe(fooData => {
   AsyncBarData().subscribe(barData => {
      ... perform actions using fooData and barData
   })
})

Is there a more efficient approach to handle this? The nested subscriptions can make the code less readable, especially if dealing with multiple AsyncData sources.

Answer №1

If you're used to working with async/await, you may find it challenging to replicate the same functionality with .subscribe callbacks in RxJS. It's important to avoid nesting subscribe calls and instead use higher order Observable operators like mergeMap or combineLatest to handle multiple emissions smoothly:

combineLatest(AsyncFooData(), AsyncBarData()).subscribe([fooData, barData] => {

});

The choice of function depends on how your foo and bar sources emit values:

  • combineLatest - Emits each time any source emits (but only after all sources have emitted at least once).
  • zip - Syncs emissions, emitting pairs once each Observable has emitted once.
  • forkJoin - Emits when all source observables complete.
  • merge - Emits whenever any source emits, without combining outputs.

For more options, check out: https://www.learnrxjs.io/operators/combination/

Answer №2

Looking for a cleaner way to chain multiple asynchronous operations? Here's how I tackle it:

  • I utilized from() assuming that AsyncFooData returns a promise. If it returns an Observable, simply remove the from().
  • Avoid unnecessary multiple subscriptions.
  • Use pipe() to neatly chain the necessary operators for a streamlined approach.
  • subscribe() is triggered after all operations are completed.
  • Style A passes the result from foo all the way to subscribe's next function.
  • Style B only considers the result of the last async operation.

Please note: These examples are provided to illustrate concepts/approaches and may have some syntax errors due to lack of IDE syntax check.

// A: implementing both foo and bar
from(AsyncFooData()).pipe(
  concatMap(foo => AsyncBarData().pipe(
    map(bar => ({foo, bar})
  )),
  tap(val => console.log(val), // add more operators here...
).subscribe(({foo, bar}) => {
  // perform actions with foo and bar
})

// B: when foo is solely used to retrieve bar (no necessity to pass along foo)
from(AsyncFooData()).pipe(
  concatMap(foo => AsyncBarData(foo)), // assuming foo is merely for retrieving bar
  tap(val => console.log(val), // add more operators here...
).subscribe(bar => {
  // do something with bar
})

Answer №3

Utilize the zip function to retrieve and manipulate both fooData and barData simultaneously.

zip(AsyncFooData(), AsyncBarData()).subscribe([fooData, barData]) => {})

In this example, we are using zip, however, you can explore other operators like combineLatest depending on your specific requirements.

I choose not to elaborate on the distinctions between zip and combineLatest in order to keep this answer concise. For a more detailed explanation with illustrations and examples, refer to these resources:

(1) Official documentation

(2) Interactive marble diagrams

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