Obtain the combination of values within an array object

I am attempting to write the specifications for a function that can take records of any structure and convert the values into a discriminated union. For example:

const getKeys = <T extends {key: string}>(items: T[]): T['key'] => {
    // ...
}

// keys should have type "foo" | "bar"
// but currently has type string
const keys = getKeys([{ key: "foo" }, { key: "bar" }])

// keys2 should have type "baz" | "qux"
// but currently has type string
const keys2 = getKeys([{ key: "foo" }, { key: "qux" }])

Unfortunately, keys and keys2 are being assigned the type of string instead.

My goal is to achieve a similar API as shown in the following working example, but using records:

const getKeys = <T extends string>(items: T[]): T => {
    // ...
}

// keys has type "foo" | "bar"
const keys = getKeys(["foo", "bar"])

// keys2 has type "baz" | "qux"
const keys2 = getKeys(["baz", "qux"])

Is there a way to achieve this?

Requirements

  • Usage of as const on the argument must be avoided

Answer №1

Instead of using const assertion, another option would be to utilize const type parameters which were introduced in Typescript 5.0.

Prior to this, TypeScript would infer a more general type for objects; however, by incorporating const type assertions, the compiler is instructed to retain the exact type without broadening it.

Here's an example of how to implement this:

const getKeys = <const T extends { key: string }>(items: T[]): T['key'] => {
  return {} as any
};

// keys should have type "foo" | "bar"
const keys = getKeys([{ key: 'foo' }, { key: 'bar' }]);

// keys2 should be either "baz" or "qux"
const keys2 = getKeys([{ key: 'bar' }, { key: 'qux' }]);

Explore this further in the playground.

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