In Typescript, you can create an object that implements an interface using a single expression like this:
=> return {_ : IStudent = { Id: 1, name: 'Naveed' }};
Is it possible to achieve this in just one statement without the need for separate 'create' and 'return' statements?
In a return statement, you cannot add a type directly (although there is a proposal for a different type assertion that allows checking without enforcing a specific type yet incorporated into the language).
However, you can specify a return type for your arrow function: `(): IStudent => ({ Id: 1, name: 'Naveed' })
You can also create a helper function to assist in creating such objects:
function asType<T>(value: T) {
return value;
};
type IStudent = { Id: number, name: string}
let fn = () => asType<IStudent>({ Id: 1, name: 'Naveed' });
Please note: Using regular type assertions like as or <> will type the object but may allow unintended errors to slip through, such as excess properties. It can still be an option in certain cases:
function asType<T>(value: T) {
return value;
};
type IStudent = { Id: number, name: string}
let fn = () => ({ Id: 1, name: 'Naveed', wops: "" }) as IStudent;
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