I am attempting to organize an array based on the win and lose ratio of each player.
This is how my code currently looks:
const array = [{playerName: 'toto', win: 2, lose: 2}, {playerName: 'titi', win: 0, lose: 0}, {playerName: 'tata', win: 3, lose: 1}];
array.sort((a, b) => a.win / a.lose || b.win / b.lose);
console.log(array);The positioning of player 'titi' above player 'toto' in the sorted array is confusing me.
Your sort function has a few issues that need to be addressed. Firstly, when dividing by a.lose and b.lose, you're encountering the problem of division by zero in your sample data resulting in Infinity. Secondly, the callback function for a sort should return either a negative number, 0, or a positive number based on whether a should come before, equal to, or after b. However, due to your current logic, it will always return a positive number. To fix this, consider using the following code snippet:
const array = [{
playerName: 'toto',
win: 2,
lose: 2
}, {
playerName: 'titi',
win: 0,
lose: 0
}, {
playerName: 'tata',
win: 3,
lose: 1
}];
array.sort((a, b) => {
if (a.win + a.lose == 0) return 1;
if (b.win + b.lose == 0) return -1;
return b.win / (b.win + b.lose) - a.win / (a.win + a.lose);
});
console.log(array);to provide more clarity:
If the compareFunction(a, b) results in a value greater than 0, then place b before a in the sorted array.
In this particular scenario, using 1/0 leads to a value of Infinity, which is considered true and causes it to skip the calculation for the b part. Returning true has the same effect as returning 1.
Implement a comparison function that sorts players based on the sum of their wins and losses.
const sortPlayers =(a, b) => {
if (a.win + a.lose + b.win + b.lose === 0) {
return 0
} else if (a.win + a.lose === 0 && b.win + b.lose !== 0) {
return 1
} else if (a.win + a.lose !== 0 && b.win + b.lose === 0) {
return -1
} else if ((a.win/(a.win + a.lose) > (b.win/(b.lose + b.win)))) {
return -1
} else if ((a.win/(a.win + a.lose) < (b.win/(b.lose + b.win)))) {
return 1
} else {
return 0
}
}
const array = [{playerName: 'toto', win: 1, lose: 0}, {playerName: 'titi', win: 0, lose: 0}];
array.sort((a, b) => sortPlayers(a, b));
console.log(array)
Your array sorting solution has been discovered! It's presented in a way that is easy to understand. This particular code snippet arranges the elements in descending order based on the win or lose index parameter. Check out the modified version of your original code below:
const array = [
{playerName: 'toto', win: 1, lose: 0},
{playerName: 'titi', win: 0, lose: 0}
];
array.sort((a, b) => {
if(a.win > b.win || a.lose < b.lose) {
return 1;
}
return -1;
});
console.log(array);If you need to change the order, simply swap "<" with ">" and vice versa.
It is important for the sort function to output an integer that specifies the item's order.
Instead, you seem to be returning the OR (||) operation as a result.
Please verify:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
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