Possibility for Automatic Type Inference in Generics

Is there a way to have a method infer the type of function parameter without specifying its generic? Currently it is 'GET' | 'POST', but I only need the literal 'GET'

const func = <Params, Method extends "GET" | "POST" = "GET" | "POST">
({params, method}: {params?: Params, method: Method}) => {}

func<{qwe: 123}>
({method: 'GET'})

TS Playground

const func = <Params, Method extends "GET" | "POST">
({params, method}: {params?: Params, method: Method}) => {}

func<{qwe: 123}>
({method: 'GET'})

This code currently requires explicit specification of the generic method, but ideally I would like for only the params to be specified and the method to be inferred automatically from the function parameters.

Answer №1

To delve deeper into type narrowing, you can visit the following link: https://www.typescriptlang.org/docs/handbook/2/narrowing.html

Regarding your issue, it seems like implementing a function overload might be necessary. However, based on the limited information provided in your question, I recommend considering a different design approach. Maybe avoiding a generic use-case as this particular scenario doesn't require such generality. The API call methods have remained consistent and are unlikely to change soon. Instead of seeking a generic solution, focus on narrowing down to a fixed type.


Your query appears somewhat ambiguous. It's crucial to be wary of falling into the XY Problem trap, where you present a solution rather than discussing the actual problem at hand.

A potential solution could involve utilizing a typeguard. To infer a type from a value (excluding boolean), employing a typeguard is typically the route to take.

If your objective is to deduce the parameter type (rather than the value), incorporating a function overload would be essential.

I've outlined an example of a Typeguard system that may be tailored to suit your specific situation. While the syntax differs from a standard typeguard, the underlying principle remains similar to type-narrowing techniques.

type Methods = "GET" | "POST";
function func<Params>(method: Methods, params?: Params) {
    method;
    
    if (method === "GET") {
        method;
        
    }

    method;
    
    if (method === "GET") {
        method;
        
        return;
    }

    method;
}

Here's an authentic example of a "typeguard".

type StringOrNumber = string | number;
function narrowStringOrNumber(value: StringOrNumber): value is string {
    if (typeof value === "string") {
        return true;
    }

    return false;
}

const a: StringOrNumber = "Hello";

a; // StringOrNumber
if (narrowStringOrNumber(a)) {
    a; // string
}

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