Remove all keys of type BaseType from objects that are children of BaseType

There are two types: BaseType and BabyType.

export type BaseType = {
    id: string
}
export type BabyType = BaseType & {
    name: string 
};

In a generic layer where <T extends BaseType> is used, the item being dealt with is actually a 'BabyType' object.

updateItem(item: T): Promise<T> {
        console.log(data) // {id: '6495f70a317b446b083f', name: 'Test'}

The goal in this layer is to dynamically remove the 'id' from the data while retaining all keys defined in BabyType.

The expected result should be:

console.log(data) // {name: 'Test'}

Attempts were made:

type OmitType = Omit<T, keyof BaseType>;
console.log(data as OmitType)

Unfortunately, the above approach did not work. The 'id' key still appeared in the console output.

Is there a solution to remove all key/value pairs that originate from BaseType?

Answer №1

Runtime behavior remains unaffected by TypeScript. The as assertion only impacts type inference in TypeScript and does not alter the underlying JavaScript object. This serves as a reminder why it is advisable to steer clear of assertions, as they have the potential to mislead regarding types.

A straightforward solution involves destructuring the item object into separate entities: id and rest:

export type MainType = {
    id: string;
};
export type ChildType = BaseType & {
    name: string;
};

function modifyItem(item: BabyType){
    const {id, ...rest} = item;

    rest
    // ^? const rest = {name: string
}

Answer №2

It seems like achieving this without using any external libraries is not feasible.

Here's a helpful discussion on how to get keys of a Typescript interface as an array of strings

Shoutout to @firewonder for providing valuable insights. I ultimately implemented your code solution.

const {id, ...rest} = item;

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