I've created a function that removes all zero values... How can I modify it to also delete 0 with a plus or minus sign? Currently, only +0 values are being removed. What should I add to my RegEx?
Here's my current code:
// Transform values
public transformAmount(val: number) {
// console.log('Value', val, val.toLocaleString('de-DE', { maximumFractionDigits: 0 }));
return val.toLocaleString('de-DE', { maximumFractionDigits: 0 }).replace(/^-0+/, '');
}
It is important to remember that your string may not necessarily start with -0. Without knowing the specific input, it is necessary to use a regex that accounts for all occurrences of 0, -0, and +0 in the text.
.replace(/((-|\+)?0)/, '');
There is some uncertainty about whether the regex /^-0+/ would work for +0, as it suggests that the beginning of the string should be a minus sign, so it would only match with -0.
If you want to replace both +0 and -0, you can use the following regex:
/^[-+]?[0]$/g
Here, the ^ symbol asserts the position at the start of the string and the brackets [] indicate matching characters present in it.
Here is an alternative regular expression that will remove all specified characters:
.replace(/^[-0+]+/, '');
"+-0A" // becomes "A"
"+-0+-A" // becomes "A"
"A+-0+-" // remains "A+-0+-"
If you only want to remove:
0
+0
-0
Then use the following code:
.replace(/^[-+]?0/, '');
If you only want to remove:
+0
-0
then use this code:
.replace(/^[-+]0/, '');
If you want to remove these patterns anywhere in the string, remove the leading ^ and add the g modifier like so:
.replace(/[-+]0\b/g, ''); // \b - indicates word boundary, so +0123 will not be affected.
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