Removing keys from a generic object using Typescript

Currently, I'm working on creating a higher-order function called without that will generate a new object without the specified keys.

I am struggling with getting the keys in the reducer to be of type keyof T as Object.keys returns an array of string[] instead of Array<keyof T>. If it returned the latter, I believe it would solve the issue. Is there something obvious regarding types that I am missing here for a solution?

const without = <T>(object: T) => (...parts: Array<keyof T>) => {
    return Object.keys(object).reduce((acc, key) => {
        // `key` is of type `string`, not `keyof T`
        if (!parts.includes(key)) {
            acc[key] = object[key];
        }
        return acc;
    }, {} as Omit<T, typeof parts[number]>);
};

const obj = { a: 1, b: 2, c: 3 };
const result = without(obj)('a', 'c');

TS Playground

Answer №1

Object.keys will provide a return of string[] due to the reasons specified in this source. To make it function, type assertions are necessary.

const without = <T>(object: T) => <K extends keyof T>(...parts: Array<K>): Omit<T, K> => {
    return (Object.keys(object) as Array<keyof T>).reduce((acc, key) => {
        if (!parts.includes(key as any)) {
            acc[key] = object[key];
        }
        return acc;
    }, {} as T);
};

const obj = { a: 1, b: 2, c: 3 };
const result = without(obj)('a', 'c');

Playground Link

The assertion to Array<keyof T> has been made along with changing the initial value type of reduce to T. This alteration enables the assignment acc[key] = object[key]. While T[keyof T] can be assigned to itself,

Omit<T, typeof parts[number]>[keyof T]
cannot. Consequently, T becomes assignable to
Omit<T, typeof parts[number]>
.

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