Restrict the parameter type using a type predicate

How can I effectively narrow types based on the value of a single field in TypeScript? It seems that using type predicates may not be working as expected to narrow down the types of other parameters within a type. Is there a way to ensure correct type narrowing in this scenario?

export function isTrue(input: boolean | undefined | null): input is true {
  return input === true;
}

type Refine =
  | {
      b: true;
      c: 'bIsTrue';
    }
  | {
      b: undefined;
      c: 'bIsUndefined';
    }
  | {
      b: false;
      c: 'bIsFalse';
    };

export function example() {
  const example = (null as unknown) as Refine;

  if (example.b === true) {
    example.b;  // Type is now: true
    example.c;  // Type is now: 'bIsTrue'
  }

  if (isTrue(example.b)) {
    example.b;  // Type is now: true
    example.c;  // Type is now: 'bIsTrue' | 'bIsUndefined' | 'bIsFalse'
  }
}

Answer ā„–1

One option is to narrow down the entire object initially and then access its properties:

function checkForTrueBProperty<T extends { b: unknown }>(object: T): object is T & { b: true } {
  return object.b === true;
}

declare const refineObject: Refine;
if (checkForTrueBProperty(refineObject)) {
  refineObject.b;  // Type will be: true
  refineObject.c;  // Type will be: 'bIsTrue'
}

If you want to test a specific property by passing it as an argument, you can use another generic:

function checkForTrueProperty<P extends PropertyKey, T extends Record<P, unknown>>(object: T, prop: P): object is T & Record<P, true> {
  return object[prop] === true;
}

declare const refineObject: Refine;
if (checkForTrueProperty(refineObject, 'b')) {
  refineObject.b;  // Type will be: true
  refineObject.c;  // Type will be: 'bIsTrue'
}

Answer ā„–2

Regrettably, the TypeScript team has officially declared that they are unwilling to address this specific scenario due to performance considerations. As an alternative approach, you can utilize types and typeguards. For instance:

interface First {
    x: true;
    y: "xIsTrue";
}

interface Second {
    x: undefined;
    y: "xIsUndefined";
}

interface Third {
    x: false;
    y: "xIsFalse";
}

type Finalize = First | Second | Third;

function isFirst(finalize: Finalize): finalize is First {
    return finalize.x === true;
}

function sample() {
    const sample = (null as unknown) as Finalize;

    if (sample.x === true) {
        sample.x;  // Type is: true
        sample.y;  // Type is: 'xIsTrue'
    }

    if (isFirst(sample)) {
        sample.x;  // Type is: true
        sample.y;  // Type is: 'xIsTrue'
    }
}

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