Searching through all values can be done by following these steps

Question

Searching through all values can be done by following these steps

Need help with implementing a search feature that can search all values in Angular2. Here's the current code snippet:

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
  name: 'filter'
})
export class FilterPipe implements PipeTransform {

  transform(projects: any, search: any): any {
    if(search === undefined) return projects;

    return projects.filter(function(project)
    {
      return project.name.toLowerCase().includes(search.toLowerCase());
    })

  }

}

Currently, this code only searches by name. How can it be modified to search all values in the table (e.g., id, name, surname, country, etc.)?

angular typescript

Answer 1

Answer №1

 let filteredProjects = projects.filter(function(project)
{
      return project.name.toLowerCase().includes(search.toLowerCase())
      ||
      return project.id.toLowerCase().includes(search.toLowerCase())
      ||
      return project.surname.toLowerCase().includes(search.toLowerCase())
      ||
      ...
       ;
})

Alternatively, you may find this resource on Array filtering on multiple fields helpful.

Answer 2

 let filteredProjects = projects.filter(function(project)
{
      return project.name.toLowerCase().includes(search.toLowerCase())
      ||
      return project.id.toLowerCase().includes(search.toLowerCase())
      ||
      return project.surname.toLowerCase().includes(search.toLowerCase())
      ||
      ...
       ;
})

Alternatively, you may find this resource on Array filtering on multiple fields helpful.

Answer 3

Answer №2

If the object is at a single level, you can iterate through all the keys and combine their values before conducting the comparison.

This process would resemble something like the following:

function search(projects, search) {
    return projects.filter(p => {
        return Object
            .keys(p) // retrieve all keys
            .map(k => p[k]) // extract all values
            .reduce((prev, current) => prev + current, '') // concatenate
            .toLowerCase() // convert to lowercase
            .includes(search.toLowerCase()); compare
    });

Alternatively, in pipe form:

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
    name: 'filter'
})
export class FilterPipe implements PipeTransform {

    transform(projects: any, search: any): any {
         if(search === undefined) return projects;
         return projects.filter(p => {
            return Object
                .keys(p)
                .map(k => p[k])
                .reduce((prev, current) => prev + current, '')
                .toLowerCase()
                .includes(search.toLowerCase());
        });

    }

}

Answer 4

If the object is at a single level, you can iterate through all the keys and combine their values before conducting the comparison.

This process would resemble something like the following:

function search(projects, search) {
    return projects.filter(p => {
        return Object
            .keys(p) // retrieve all keys
            .map(k => p[k]) // extract all values
            .reduce((prev, current) => prev + current, '') // concatenate
            .toLowerCase() // convert to lowercase
            .includes(search.toLowerCase()); compare
    });

Alternatively, in pipe form:

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
    name: 'filter'
})
export class FilterPipe implements PipeTransform {

    transform(projects: any, search: any): any {
         if(search === undefined) return projects;
         return projects.filter(p => {
            return Object
                .keys(p)
                .map(k => p[k])
                .reduce((prev, current) => prev + current, '')
                .toLowerCase()
                .includes(search.toLowerCase());
        });

    }

}

Searching through all values can be done by following these steps

Answer №1

Answer №2

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