Selecting the appropriate color code based on a specified value

Question

Selecting the appropriate color code based on a specified value

If the value of zoneTempDiff1 falls below 1.5, consider using temp: 1 color. If it exceeds 1.5, opt for temp: 2 color. The same logic applies to all different values such as -1, -2, 0, 1, 2, 3, 4, or 5, each corresponding to a specific color code. In cases where the value is greater than +6 or less than -6, use the respective colors for temp:+6 or temp:-6.


floor.entities.forEach(elementId => {
  let objTemp: any = {};
  objTemp.currentTemp = 68;
  objTemp.desiredTempHeating = 70.5;

  let zoneTempDiff1 = objTemp.currentTemp - objTemp.desiredTempHeating;
  let tempColor1 = this.temperatureColors.filter(color => zoneTempDiff1 < (color.temp + 1) && zoneTempDiff1 > (color.temp - 1));
  objTemp.tempColorToInsert = tempColor1.color;

  floor.droppeditem.push(objTemp);
});


temperatureColors: any = [
   { color: '#50B3D3', temp: -6 },
   { color: '#25CBE4', temp: -4 },
   { color: '#25CBE4', temp: -3 },
   { color: '#7EE2DD', temp: -2 },
   { color: '#7EE2DD', temp: -1 },
   { color: '#89DE6F', temp: 0 },
   { color: '#89DE6F', temp: 1 },
   { color: '#D2E143', temp: 2 },
   { color: '#D2E143', temp: 3 },
   { color: '#FDCB31', temp: 4 },
   { color: '#FDCB31', temp: 5 },
   { color: '#F59A4A', temp: 6 }
];

javascript arrays typescript

Answer 1

Answer №1

Could you clarify your question?

The function is invoked like this:

getColor(68, 78, colors);

We provide the current temperature, desired temperature, and an array of color objects as arguments.

const getColor = (current, desired, colors) => {

We calculate the temperature difference and round it to the nearest whole number.

const diff = Math.round(current - desired);

We determine the index of the last element in the colors array.

const last = colors.length - 1;

Next, we check if the difference is less than or equal to the temp property specified in the first color object of our array. If so, we return that color and finish.

if (diff <= colors[0].temp) return colors[0].color;

A similar comparison here but now we are looking for if the difference is greater than or equal to the temp in the last color object in the array.

if (diff >= colors[last].temp) return colors[last].color;

If neither condition is met, we iterate through the array and use find to locate the object with a temp value that matches the diff.

return colors.find(color => diff === color.temp).color;

Is this clear enough?

// Code snippet ***

Let's introduce a new function.

This time around, we directly compute the difference and utilize Array.reduce to pinpoint the color object from the array. While it's concise (almost like a one-liner), it may require more effort to understand. However, it offers greater flexibility since every temperature variation doesn't need to be included in the input array.

 // Another code snippet ***

Understanding Reduce

The reduce method operates on an array by applying a callback function to each element and eventually producing a single value.

For instance, given an array [1, 2, 3], we can reduce it to the sum of all elements. The magic happens within the reduce callback function.

The callback receives four parameters: accumulator, current element, current element index, and the array itself.

...

Answer 2

Could you clarify your question?

The function is invoked like this:

getColor(68, 78, colors);

We provide the current temperature, desired temperature, and an array of color objects as arguments.

const getColor = (current, desired, colors) => {

We calculate the temperature difference and round it to the nearest whole number.

const diff = Math.round(current - desired);

We determine the index of the last element in the colors array.

const last = colors.length - 1;

Next, we check if the difference is less than or equal to the temp property specified in the first color object of our array. If so, we return that color and finish.

if (diff <= colors[0].temp) return colors[0].color;

A similar comparison here but now we are looking for if the difference is greater than or equal to the temp in the last color object in the array.

if (diff >= colors[last].temp) return colors[last].color;

If neither condition is met, we iterate through the array and use find to locate the object with a temp value that matches the diff.

return colors.find(color => diff === color.temp).color;

Is this clear enough?

// Code snippet ***

Let's introduce a new function.

This time around, we directly compute the difference and utilize Array.reduce to pinpoint the color object from the array. While it's concise (almost like a one-liner), it may require more effort to understand. However, it offers greater flexibility since every temperature variation doesn't need to be included in the input array.

 // Another code snippet ***

Understanding Reduce

The reduce method operates on an array by applying a callback function to each element and eventually producing a single value.

For instance, given an array [1, 2, 3], we can reduce it to the sum of all elements. The magic happens within the reduce callback function.

The callback receives four parameters: accumulator, current element, current element index, and the array itself.

...

Selecting the appropriate color code based on a specified value

Answer №1

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