Set up TypeScript to automatically deduce the type of generics based on a specific function name within the

My goal is to minimize redundancy in common code patterns within a project by setting up TypeScript to perform a sort of enchantment - deducing a generic type based on the existence of a function with a specific name.

Picture me utilizing a framework that includes a getStuff function with the following structure:

function getStuff<T> (): T {}

Please note that getStuff() does not accept any arguments, so why/how can it include a generic type? Well, in this framework, thanks to some mystical framework magic, it will actually return the value from another function named loadStuff found in the same file.

function loadStuff () {
  return { a: 1, b: 2 }
}

function something () {
  const stuff = getStuff()

  if (stuff.a === 1) ... // true
}

The issue arises because TypeScript is unaware of this framework sorcery, hence the need for the generic provided by the framework.

To add typing to stuff, I have to manually provide a hint using the generic attached to getStuff.

const stuff = getStuff<{ a: number, b: number }>()

if (stuff.a === 'hello') ... // excellent, now I receive auto-completion on .a and a type error

What I aim to accomplish is to eliminate the need to constantly provide this manual hint to getStuff each time by utilizing a global configuration.

In simple terms, what I wish to convey to TypeScript is that, universally within this project, when I utilize getStuff<T>, automatically populate <T> with the return type of a function located at the top scope of the same file (module) named loadStuff.

I am content with having these specific names for loadStuff and getStuff that must be adhered to precisely.

I acknowledge that I could achieve this through code generation, but I would much prefer to avoid that route if possible. It would be fantastic if TypeScript could be configured 'magically' to handle this dynamically and globally for the entire project. Is this achievable?

Answer №1

I'm pretty confident that achieving exactly what you've described may not be possible (but I would love to see if someone can prove me wrong). Here's an alternate approach:

Try implementing this method once for each file:

const getThisStuff: () => ReturnType<typeof loadStuff> = getStuff;

Then simply use it like this:

const stuff = getThisStuff();

Playground link

This method could serve as your version of "code generation," but in case it's not what you had in mind...

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