How can I sort a list of 2 strings with dates inside them so that the earlier one always comes first? The date is always after the second comma.
For example,
const example =
["AAA,5,2020-09-17T21:14:09.0545516Z",
"AAA,0,2020-09-03T20:38:08.3946643Z"]
sortStrings(example: string[]) {
// how to sort to let earlier date come first
}
const data = ["ZZZ,10,2021-11-25T15:30:45.032612Z", "BBB,-5,2022-01-08T12:20:59.186422Z"]
data.sort((x, y) => new Date(x.split(",")[2]).getTime() - new Date(y.split(",")[2]).getTime())
console.dir(data);Be cautious, this code snippet is just a simple example and not the most optimized way to sort an array based on dates.
arrangeWords(inputList: string[]){
inputList.sort((word1, word2) => {
var dataWord1 = word1.split(",");
var dataWord2 = word2.split(",");
var dateWord1 = new Date(dataWord1[dataWord1.length - 1]);
var dateWord2 = new Date(dataWord2[dataWord2.length - 1]);
return (dateWord1 > dateWord2 ? 1 : dateWord1 < dateWord2 ? -1 : 0);
}
}
When considering the terms ascending and descending, they play a crucial role in answering certain questions. To illustrate this, here is a sample scenario:
const example = ["AAA,5,2020-09-17T21:14:09.0545516Z",
"AAA,0,2020-09-03T20:38:08.3946643Z"
]
function desc(a, b) {
a = a.split(",").pop();
b = b.split(",").pop();
let aDate = new Date(a);
let bDate = new Date(b);
if (aDate.getTime() > bDate.getTime()) {
return -1;
}
if (aDate.getTime() < bDate.getTime()) {
return 1;
}
return 0;
}
function asc(a, b) {
a = a.split(",").pop();
b = b.split(",").pop();
let aDate = new Date(a);
let bDate = new Date(b);
if (aDate.getTime() < bDate.getTime()) {
return -1;
}
if (aDate.getTime() > bDate.getTime()) {
return 1;
}
return 0;
}
example.sort(desc);
console.log(example);
example.sort(asc);
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