I am trying to create a TypeScript function that accepts an argument matching one of two conditions:
type A = {
x: string
}
type B = {
y: string
}
function testFunc(param: A | B) {
...
}
However, TypeScript allows me to call the function with both keys:
testFunc({x: "x", y: "y"})
Shouldn't the union type restrict the function to only accept either A or B?
Playground showcasing the issue here
To achieve this, you can utilize function overloads:
type First = {
a: string
}
type Second = {
b: string
}
function check(inputs: First): void;
function check(inputs: Second): void;
function check(inputs: (First | Second)) {
console.log(inputs)
}
check({
a: 'x',
}) // successful
check({
b: 'm'
}) // successful
check({
a: 'x',
b: 'm'
}) // error
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