What is the method in TypeScript to "spread" a generic type across a union?
type Box<T> = { content: T };
type Boxes<string | number> = Box<string> | Box<number>;
(Given that we are aware of when to use Boxes
versus Box
)
What is the method in TypeScript to "spread" a generic type across a union?
type Box<T> = { content: T };
type Boxes<string | number> = Box<string> | Box<number>;
(Given that we are aware of when to use Boxes
versus Box
)
Interestingly, the type inference feature can handle this automatically:
type Container<T> = { value: T }
type Containers<T> = T extends infer A ? Container<A> : never;
The compiler is clever enough to separate them all out:
type C = Containers<string | number | {x: number} | {z: string} | boolean>
Type C
expands like so:
type C = Container<string> |
Container<number> |
Container<false> |
Container<true> |
Container<{
x: number;
}> |
Container<{
z: string;
}>
After reviewing your provided sample code, it appears that you are seeking to define a generic type that is restricted to a union of types. Below are some options that may suit your needs:
type Box<T> = { item: T };
type BoxA = Box<string | number>;
type BoxB = Box<string> | Box<number>
type BoxC<T extends string | number> = Box<T>;
It's worth noting that the term Spread holds a specific meaning in JavaScript syntax, which might be causing confusion based on its use in your query.
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