I've been diving into TypeScripe recently and I'm working on creating some useful ts types.
For instance:
Here's an interface I've come up with:
interface Student{
name: string,
id: number,
gender: string
}
Now, I need to extract the keys from this interface to create a new Array type like so
type Arr = ['name', 'id', 'gender']
Any ideas on how I can write a utility type to achieve this?
Here is the solution you've been searching for: . For additional solutions, check out this link https://github.com/microsoft/TypeScript/issues/13298.
To address your specific issue, utilizing the keyof keyword to obtain a union of keys (keyof Student) is necessary, followed by passing it to the TupleUnion helper function. It's important to note that the sequence of literal values in the union may not always be predictable.
Explore more at https://tsplay.dev/Nr922w
It puzzles me why others are complicating it with tuples, unions, and so on. Please correct me if I'm mistaken, but my approach has always been straightforward and effective without any problems:
const keys: (keyof Student)[] = [];
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