Strategies for eliminating squizzle when passing variable with type value

While f(c) below has squizzle which is fine, I prefer not to have them for f(va). Is there a way to achieve this?

    type TParam = 'a' | 'b';
    function f(param: TParam) {
      alert(param);
    }

    f('a');
    f('b');
    f('c');
    let va = 'a';
    f(va);

Answer №1

The default data type assigned to va in this scenario is usually a string, which typically suits the requirements. However, you have the option to specify a narrower data type for va based on your specific needs:

let va: 'a' = 'a';
f(va)

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