Substitute all instances of null bytes

I need to remove null bytes from a string. However, after replacing the null bytes \u0000 in the string

let data = {"tet":HelloWorld.\u0000\u0000\u0000\u0000"}
let test = JSON.parse(data).tet.replace("\u0000", "");

I always end up with the following value:

 HelloWorld.[][][][]

These are not array brackets or anything like that.

All I want is the value HelloWorld. How can I achieve this?

The solution turned out to be replacing all bytes.

.replace(new RegExp("\u0000", "g"), "");

Answer №1

When using a regular string replace function, only the first occurrence is replaced.

However, if you utilize a regex with a global flag, it will replace all occurrences instead.

Here is an example snippet:

console.log("bar bar".replace("bar","foo"));
console.log("bar bar".replace(/bar/g,"foo"));

let data = {"test":"HelloWorld.\u0000\u0000\u0000\u0000"};

console.log("before: " + data.test);
console.log("before (stringified): " + JSON.stringify(data.test));

// removing all the NULL unicode characters
data.test = data.test.replace(/\u0000/g,'');

console.log("after  (stringified): " + JSON.stringify(data.test));

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