swap out an element in an array with an extra element

Question

swap out an element in an array with an extra element

My array contains elements with both id and des properties. I would like to add an additional property like value:0 to each object in the array. I achieved this using a loop.

let data = [
    {
        "id": 1001,
        "des": "aaa"
    },
    {
        "id": 1002,
        "des": "aaa"
    }
];

for (let i = 0; i < data.length; i++) {
    let tempObj = {
        "id": data[i].id, "des": data[i].des, "value": 0
    }
    data[i] = tempObj;
}

Is there a way to accomplish this without using a loop in JavaScript? Are there any built-in JavaScript functions that can help with this?

javascript arrays angular typescript ecmascript-6

Answer 1

Answer №1

One cannot achieve this without incorporating a loop, but it is possible to streamline the code by utilizing the Array#map method along with the Object.assign method (or leveraging the spread syntax in ES6).

let data = [{
    "id": 1001,
    "des": "aaa"

  },  {
    "id": 1002,
    "des": "aaa"
  }
];

var res = data.map(o => Object.assign({
  value: 0
}, o));


console.log(res);

// alternatively, the spread syntax can be used
var res1 = data.map(o => ({ ...o, value: 1 }));


console.log(res1);

Answer 2

One cannot achieve this without incorporating a loop, but it is possible to streamline the code by utilizing the Array#map method along with the Object.assign method (or leveraging the spread syntax in ES6).

let data = [{
    "id": 1001,
    "des": "aaa"

  },  {
    "id": 1002,
    "des": "aaa"
  }
];

var res = data.map(o => Object.assign({
  value: 0
}, o));


console.log(res);

// alternatively, the spread syntax can be used
var res1 = data.map(o => ({ ...o, value: 1 }));


console.log(res1);

Answer 3

Answer №2

A great way to iterate through and modify each element in an array is by utilizing the map method along with the spread operator (...), which simplifies the process of duplicating all properties from one object to another:

data.map(item => ({ ...item, newValue: 0 }));

Answer 4

A great way to iterate through and modify each element in an array is by utilizing the map method along with the spread operator (...), which simplifies the process of duplicating all properties from one object to another:

data.map(item => ({ ...item, newValue: 0 }));

Answer 5

Answer №3

If you want to avoid looping through all elements internally, you can utilize the .map() method.

Personally, I prefer to use Object.assign() when creating a new object.

let data = [{
    "id": 1001,
    "des": "aaa"
  },
  {
    "id": 1002,
    "des": "aaa"
  }
];

let newData = data.map(el => Object.assign( el, {value: 0} ));
console.log(newData);

Answer 6

If you want to avoid looping through all elements internally, you can utilize the .map() method.

Personally, I prefer to use Object.assign() when creating a new object.

let data = [{
    "id": 1001,
    "des": "aaa"
  },
  {
    "id": 1002,
    "des": "aaa"
  }
];

let newData = data.map(el => Object.assign( el, {value: 0} ));
console.log(newData);

Answer 7

Answer №4

To iterate over the array and incorporate the spread operator syntax, you can use the map method.

let collection = [{
              "id": 1001,
              "description": "aaa"

            },

            {
                "id": 1002,
                "description": "aaa"

            }
        ];
    
collection = collection.map(item => ({...item, value: 0}))
console.log(collection)

Answer 8

To iterate over the array and incorporate the spread operator syntax, you can use the map method.

let collection = [{
              "id": 1001,
              "description": "aaa"

            },

            {
                "id": 1002,
                "description": "aaa"

            }
        ];
    
collection = collection.map(item => ({...item, value: 0}))
console.log(collection)

swap out an element in an array with an extra element

Answer №1

Answer №2

Answer №3

Answer №4

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