Swapping out an Array of Objects with a new Array in JavaScript

Question

Swapping out an Array of Objects with a new Array in JavaScript

I am working with an Array of Items, each of which has a set of Properties. One specific property is called config: object[], which is an array of Objects.

While I usually provide the complete object with the correct config array of objects, there are times when I need to pass different config options for certain tests. For instance, wrong config array, empty array, etc.

Below is my code snippet:

    const connectionResources = [Array.forEach(object => object.config === [])]
    connectionResources.forEach(builtInOptions => console.log(builtInOptions))

This is what I have attempted so far. I tried to spread the Array, but unfortunately, it did not work as expected.

Could someone offer some guidance on how to achieve what I am aiming for? Essentially, I want the Array of Objects to have an empty config array property instead of the original object. How can this be accomplished?

javascript arrays typescript spread

Answer 1

Answer №1

Attempting to spread the Array was unsuccessful for me as well.

First and foremost, if you wish to spread an array, make sure to utilize the spread operator; for example, ...myArray.

Array.forEach

Furthermore, Array.prototype.forEach yields undefined, while Array.forEach is indeed undefined (unless your array is named Array, which is not recommended as it would overshadow the Array class).

To address the issue at hand, what you actually need is Array.prototype.map

let original = [{a: 3, config: [4, 5], b: 6}, {a: 13, config: [14, 15], b: 16}];

let emptyConfig = original.map(o => ({...o, config: []}));
let hundredConfig = original.map(o => ({...o, config: [100, 101, 102]}));

console.log(original);
console.log(emptyConfig);
console.log(hundredConfig);

Answer 2

Attempting to spread the Array was unsuccessful for me as well.

First and foremost, if you wish to spread an array, make sure to utilize the spread operator; for example, ...myArray.

Array.forEach

Furthermore, Array.prototype.forEach yields undefined, while Array.forEach is indeed undefined (unless your array is named Array, which is not recommended as it would overshadow the Array class).

To address the issue at hand, what you actually need is Array.prototype.map

let original = [{a: 3, config: [4, 5], b: 6}, {a: 13, config: [14, 15], b: 16}];

let emptyConfig = original.map(o => ({...o, config: []}));
let hundredConfig = original.map(o => ({...o, config: [100, 101, 102]}));

console.log(original);
console.log(emptyConfig);
console.log(hundredConfig);

Answer 3

Answer №2

Illustrative data

const library = [{
    settings: [{}, {}]
}, {
    settings: [{}, {}]
}];

No content in the settings property

library = library.map(item => {
    item.settings = [];
    return item;
});

Answer 4

Illustrative data

const library = [{
    settings: [{}, {}]
}, {
    settings: [{}, {}]
}];

No content in the settings property

library = library.map(item => {
    item.settings = [];
    return item;
});

Swapping out an Array of Objects with a new Array in JavaScript

Answer №1

Answer №2

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