Test your knowledge with this quiz on Typescript's AddOrSubtract functions

Question

Test your knowledge with this quiz on Typescript's AddOrSubtract functions

Just starting out with learning Typescript and tackling this challenge from Execute Program:

Create a function that either adds or subtracts 1 from a given number. The first argument is the number, and the second argument is a boolean. If the boolean is true, add 1; otherwise, subtract 1.

I've attempted various versions of the code below:

function addOrSubtract(x: number, y: boolean): any {
  if (y = true) {
    return x+1;
  } else {
    return x-1;
  }
  return x;
}
addOrSubtract(5, true);
addOrSubtract(5, false);

The problem I'm facing is that the test only recognizes the first condition. Even adding an additional else if (y = false) statement yields the same outcome.

Results of four tests: addOrSubtract(5, true); Expected: 6 OK! addOrSubtract(5, false); Expected: 4 but received: 6 addOrSubtract('5', true); Expected: type error OK! addOrSubtract('5', null); Expected: type error OK!

Thank you in advance

javascript typescript conditional-statements

Answer 1

Answer №1

Your current if statement is incorrect because you are using the assignment operator = instead of the equality check operator ==.

Here's the corrected code snippet -

function addOrSubtract(x: number, y: boolean): any {
  if (y == true) {
    return x+1;
  } else {
    return x-1;
  }
  return x;
}

Additionally, since variable y is of type boolean, you can directly use it in the if condition.

function addOrSubtract(x: number, y: boolean): any {
  if (y) {
    return x+1;
  } else {
    return x-1;
  }
  return x;
}

Answer 2

Your current if statement is incorrect because you are using the assignment operator = instead of the equality check operator ==.

Here's the corrected code snippet -

function addOrSubtract(x: number, y: boolean): any {
  if (y == true) {
    return x+1;
  } else {
    return x-1;
  }
  return x;
}

Additionally, since variable y is of type boolean, you can directly use it in the if condition.

function addOrSubtract(x: number, y: boolean): any {
  if (y) {
    return x+1;
  } else {
    return x-1;
  }
  return x;
}

Answer 3

Answer №2

Building upon Aman's response, you have the option to streamline this process further by implementing ternary statements.

function addOrSubtract(x: number, y: boolean): number {
  x = y ? x + 1 : x - 1;
  return x;
}

Ternary statements can be a valuable tool in TypeScript and JavaScript, offering efficiency and time-saving benefits if utilized correctly. Unless of course, your compensation is based on lines of code.

In TypeScript specifically, it is recommended to use === over == for type-safe comparisons with strict type checking.

Answer 4

Building upon Aman's response, you have the option to streamline this process further by implementing ternary statements.

function addOrSubtract(x: number, y: boolean): number {
  x = y ? x + 1 : x - 1;
  return x;
}

Ternary statements can be a valuable tool in TypeScript and JavaScript, offering efficiency and time-saving benefits if utilized correctly. Unless of course, your compensation is based on lines of code.

In TypeScript specifically, it is recommended to use === over == for type-safe comparisons with strict type checking.

Test your knowledge with this quiz on Typescript's AddOrSubtract functions

Answer №1

Answer №2

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