The callback type in TypeScript is used to define the types

I have encountered this scenario:

function createCar(name: string, callback: () => void)

function buildEngine(name: string): Engine

function createCarWithEngine(carName: string, engineName: string, callback: (param: Engine) => void) {
  let createdEngine = createdEngines.find((engine) => engine.name === engineName)
  if (!createdEngine) createdEngine = buildEngine(engineName)

  createCar(carName, () => callback(createdEngine)) // encountering an error here
}

While working in VSCode, it indicates that createdEngine might be undefined. However, the following code seems to work without any issues:

  const fn = callback(createdEngine)

  createCar(carname, () => fn)

Can anyone explain if this behavior is expected?

Answer №1

The two scenarios are not the same.

In the second scenario, you invoke `callback` within the function, while in the first scenario, you postpone the call for a later time.

This will result in the same error.

 const func = () => callback(createdEngine)

 createCar(carname, func)

This issue arises because TypeScript cannot determine what will happen with `createdEngine` since the function is being called at a later time. However, if you ensure that the type of `createdEngine` remains as an `Engine`, then it should work.

function createCarWithEngine(carName: string, engineName: string, callback: (param: Engine) => void) {
  let createdEngine = createdEngines.find((engine) => engine.name === engineName) || buildEngine(engineName)

  createCar(carName, () => callback(createdEngine)) // error occurs here
}

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