The conditional type in TypeScript is malfunctioning

Upon finishing an article discussing conditional types in TypeScript located at:

I have attempted to implement a conditional type in the following function:

function convertToIsoString<T extends number|undefined>(
  timestamp:T
): T extends number ? string : undefined {
  if (typeof timestamp === 'number') {
    return (new Date(timestamp)).toISOString() // encountered error [1]
  }
  return undefined // encountered error [2]
}

const myTimestamp:number|undefined = 1570081092848
console.log(convertToIsoString(myTimestamp))  // 2019-10-03T05:38:12.848Z

The code above generated the following type errors:

// [1] Type 'string' is not assignable to type 'T extends number ? string : undefined'
// [2] Type 'undefined' is not assignable to type 'T extends number ? string : undefined'

Frustrated by my confusion, I decided to test the code from the mentioned article:

function manipulateText<T extends string | null>(
  text: T
): T extends string ? string : null {
  return text && text.replace(/f/g, 'p') // encountered error [3]
}
const possibleText: string | null = 'foo'
console.log(manipulateText(possibleText).toUpperCase()) // POO

To my surprise, I faced a similar issue:

// [3] Type 'string' is not assignable to type 'T extends string ? string : null'

What could I be overlooking? :(

Answer №1

To ensure compatibility, you must cast the returned value as any. An unresolved issue is highlighted in the article(comments section) and can be found at this link: https://github.com/microsoft/TypeScript/issues/24929

function getIsoStringFromDatestamp<T extends number|undefined>(
  receivedAt:T
): T extends number ? string : undefined {
  if (typeof receivedAt === 'number') {
    return (new Date(receivedAt)).toISOString() as any
  }
  return undefined as any
}

const dateStamp:number|undefined = 1570081092848
console.log(getIsoStringFromDatestamp(dateStamp))

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