The element is being implicitly assigned the 'any' type due to the inability to use a 'string' type expression to index the style type

I have encountered an issue that I am unsure how to solve:

"Element implicitly has an 'any' type because expression of type 'string' can't be used to index type '{ prop_first: string; prop_second: string; }'. No index signature with a parameter of type 'string' was found on type '{ prop_first: string; prop_second: string; }'. :

const users = [
  { 'user': 'b', 'age': 12, 'active': true, warnings: [{propertyA: true, propertyB: false}] },
  { 'user': 'a',   'age': 22, 'active': false, warnings: [{propertyB: false}] }
];

const obj = {
   propertyA: 'true',
   propertyB: 'true',
};

Object.keys(obj).forEach((key, index) => {
  obj[key] = !(!!obj[key]);
});

console.log(obj);

const propertyA = true

const properties = {propertyA: true, propertyB: false}
 
const result = users.filter(user => user.warnings.length && _.some(user.warnings, obj))
console.log(result)
console.log(!!undefined)

Does anyone have any insights on how to resolve this?

Answer №1

An issue arises on the specified line:

The problem is with this code: obj[key] = !(!!obj[key]);

There is a possibility that the value of key could be a string, and applying a logical not ! directly to a string may lead to unexpected results.

Answer №2

Make sure to properly type Object.keys(obj) and obj:

const obj: Record<PropertyKey, string | boolean> = {
   propertyA: 'true',
   propertyB: 'false',
};

(Object.keys(obj) as Array<keyof typeof obj>).forEach((key, index) => {
  obj[key] = !(!!obj[key]);
});

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