The only numbers that can be typed using Typescript are odd numbers

I am looking for a way to create a type in Typescript that can check if a value is an odd number. I have searched for solutions, but all I find are hardcoded options like odds: 1 | 3 | 5 | 7 | 9. Is there a dynamic approach to achieve this using only Typescript?

In JavaScript, we can determine if a number is odd by using the expression x % 2 === 1. I am wondering if there is a method to define a type with a similar expression.

Answer №1

Affirmative, it is indeed feasible

type OddNumber<
    X extends number,
    Y extends unknown[] = [1],
    Z extends number = never
> = Y['length'] extends X
    ? Z | Y['length']
    : OddNumber<X, [1, 1, ...Y], Z | Y['length']>

type a = OddNumber<1> // 1 
type b = OddNumber<3> // 1 | 3
type c = OddNumber<5> // 1 | 3 | 5
type d = OddNumber<7> // 1 | 3 | 5 | 7

However, there are restrictions - the input must be an odd number and should not go beyond 1999 (due to TypeScript recursion limit of 1000)

sandbox

Answer №2

Perhaps the solution lies in creating a specialized class for handling this scenario?

class UniqueNumber {
    value: number;

    constructor(value: number) {
        if (value % 2 != 0)
            throw new Error("Odd number is not valid for type 'UniqueNumber'.");
        this.value = value;
    }
};

let uniqueNumber = new UniqueNumber(4);
console.log(uniqueNumber.value); // Output: 4
let oddNumber = new UniqueNumber(5); // Exception thrown here
console.log(oddNumber.value);

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