The parseFloat function only considers numbers before the decimal point and disregards

I need my function to properly format a number or string into a decimal number with X amount of digits after the decimal point. The issue I'm facing is that when I pass 3.0004 to my function, it returns 3. After reviewing the documentation, I realized that when parseFloat encounters a ., it only considers values before that and ignores any invalid characters and those that come after.

Although I understand this behavior, I still want my function to return 3.00. Is there a way to achieve this? I aim for my function to consistently output a number with specified decimal digits. I chose to use parseFloat because I require it to return either a number or null.

Below is the code snippet showing my implementation:

const toDecimal = (number: number | string, digits: number = 2): number | null => {
  switch (typeof number) {
    case 'number':
      return parseFloat(number.toFixed(digits));
    case 'string':
      const parsedDecimal = parseFloat(number);
      return isNaN(parsedDecimal)
        ? null
        : parseFloat(parsedDecimal.toFixed(digits));
    default:
      return null;
  }
}

toDecimal(3.0004)  // will return 3

Answer №1

  1. @Serpentarius made a crucial point in response to your query: "The numerical value consists of 3, 3.0, 3.00, and so forth. The additional zeros at the end are implied and extend infinitely."
  2. By inputting "3.004" as the sole parameter, the default for digits is 2, resulting in the number being fixed to "3.00" due to the use of toFixed.

If you wish for "3.004" to be accurately converted to 3.004, simply increase the precision by calling your function with:

toDecimal("3.004", 3)

Answer №2

Integrate this new function:

const convertToDecimal = (inputNum: number | string, decimalPos: number = 2) => {
  const parsedNum = toDecimal(inputNum, decimalPos)
  return parsedNum == null ? null : parsedNum.toFixed(2)
}

console.log(convertToDecimal(3.0004))  // output will be "3.00"

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