The ranking of type parameter inference in TypeScript applications

I've created a unique decorator for classes that accepts an initializer function as its argument. Inside this `initializer` function, I want to be able to return an instance that matches the class type or a derived one:

function JsonObject<T>(initializer: (json: any) => T) {
    return function (target: { new (...args: any[]): T }) {
        // ...
    }
}
@JsonObject(function (json) {
    return new Animal();
})
class Animal {
    name: string;
}

Returning an instance of the exact class works fine, but...

Detailed Overview

When trying to return an instance of a derived class, it doesn't work. While I can return a base instance, I cannot return a derived one. For example, returning a `Cat` results in an error:

@JsonObject(function (json) {
    return new Cat(); // Error.
})
class Animal{
    name: string;
}

class Cat extends Animal {
    color: string;
}

... even though a Cat is an Animal. However, it's possible to return an Animal instead of a Cat (even though incorrect), for a Cat:

@JsonObject(function (json) {
    return new Animal(); // OK, but it shouldn't be
})
class Cat extends Animal {
    color: string;
}

In-depth Explanation

The JsonObject Decorator Factory

The `JsonObject` function acts like a callback function with a generic type parameter `T`, where it returns a `T`. It then returns a function accepting a newable type that returns a `T`. This returned function is the actual class decorator.

The compiler enforces correct types in the `initializer` function, preventing mismatched types like returning a string.

Issue with Subtypes

When using subtypes, the behavior is opposite. I can return a base type from the `initializer` function, but not a derived type. An error occurs when used on the middle class of a 2-step inheritance pattern:

@JsonObject(function (json) {
    // Test case: return a base type.
    return new Animal(); // OK, but it shouldn't be: an 'Animal' is not a 'Cat'
})
@JsonObject(function (json) {
    // Test case: return an exact corresponding type.
    return new Cat(); // OK, as it should be
})
@JsonObject(function (json) {
    // Test case: return a derived type.
    return new Kitty(); // <-- Error, but it should be OK, a Kitty *is* a Cat
})
class Cat extends Animal {
    color: string;
}

class Kitty extends Cat {
    cutenessFactor: number;
}

Error: Type 'Cat' is not assignable to type 'Kitty'. Property 'cutenessFactor' is missing in type 'Cat'.

The issue arises from the compiler inferring generics based on the `initializer`, causing errors. The solution lies in inferring `T` from the "return" type of `target`. Explicitly specifying the generic type parameter resolves the issue, although redundantly:

@JsonObject<Cat>(function (json) {
    return new Kitty(); // OK, since type 'Kitty' is assignable to type 'Cat'
})
class Cat extends Animal { }

Answer №1

Were you intending to connect the decorators in a chain or did you have something else in mind?

function JsonObject<T>(initializer: (json: any) => T) {
    return function (target: { new (...args: any[]): T }) {
        return null;
    }
}


@JsonObject(function (json) {
    return new Caterpillar();
})
class Caterpillar {
    caterpillar: string;
}

@JsonObject(function (json) {
    // Example: returning an exact matching type.
    return new Butterfly(); 
})
class Butterfly extends Caterpillar {
    butterfly: string;
}

@JsonObject(function (json) {
    // Example: returning a subtype.
    return new Moth(); 
})
class Moth extends Butterfly {
    moth: string;
}

If you were referring to the above examples, they should compile without issues.

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