The TypeScript conditional return type is not functioning as expected when being tested against an extension of undefined

When testing the return type of func, it should be number if the argument arg is provided, otherwise it should be string. However, conducting tests with extending undefined does not yield the expected result. Testing against types like extending number or other normal types does work as intended.

const func = <T>(arg?:T): T extends undefined?number:string=>{
    if(arg) return 's' as any
    else return 10 as any
}
let ff = func()
ff // string - but should be number

Is there a way to utilize typescript conditional typing to determine if an argument has been passed or not?

Answer №1

For this scenario, it is recommended to utilize function overloads:

type FalsyValues = '' | null | undefined | 0 | false // no NaN

function func(): 's'
function func(arg: FalsyValues): 's'
function func(arg: unknown): 10
function func<T>(arg?: T | undefined): "s" | 10
function func<T,>(arg?: T) {
    if (arg) return 's'
    else return 10
}
let f = func() // 's'
let ff = func(0) // 's'
let fff = func(1) // 10

Playground

UPDATE

type FalsyValues = '' | null | undefined | 0 | false // no NaN

type Conditional<T> = T extends FalsyValues ? T extends unknown ? unknown extends T ? never : 's' : never : 10

function func<T extends string | null | undefined | number | boolean | object>(arg?: T): Conditional<T> {
    if (arg) {
        return 's' as Conditional<T>
    }
    else return 10 as Conditional<T>
}
let f = func('') // 's'
let ff = func(0) // 's'
let fff = func(1) // 10
let ffff = func() // 's' | 10

The primary issue arises with a function lacking an argument.

Since the argument type was not specified, I assumed it could be any value. Therefore, I have defined the FalsyValues type in case an argument is provided to the function.

UPDATE I have included additional constraints:

type FalsyValues = '' | null | undefined | 0 | false // no NaN

type Conditional<T> = T extends FalsyValues ? 's' : 10

function func<T extends string | null | undefined | number | boolean | object = null>(arg?: T): Conditional<T> {
    if (arg) {
        return 's' as Conditional<T>
    }
    else return 10 as Conditional<T>
}
let f = func('') // 's'
let ff = func(0) // 's'
let fff = func(1) // 10
let ffff = func() // 's'


Playground

Answer №2

Big thanks to captin-yossarian for guiding me to the right answer, although all I really required was the following snippet:

function customFunc<T extends any = undefined>(arg?: T): T extends undefined ? 's' : 10 {
  if (arg) {
    return 's' as any
  }
  else return 10 as any
}

let result1 = customFunc('') // 10
let result2 = customFunc(0) // 10
let result3 = customFunc(1) // 10
let result4 = customFunc() // 's'

As mentioned in the comments, setting the default parameter for conditional parameter as unknown wasn't sufficient for my needs, so utilizing T extends any = undefined did the trick.

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