There is no equality between two required types that are equivalent

When trying to assign Required<T> (where T extends A) to Required<A>, the operation fails.

Consider this simplified example:

type A = { a?: number };

type B<T extends Required<A>> = T;

type C<T extends A> {
  b: B<Required<T>>;
}

Although it seems like it should work, I encountered an error that says

Type 'Required<T>' does not satisfy the constraint 'Required<A>'
. How can I resolve this issue?

Answer №1

The issue here lies in the definition of T using <T extends A>, which allows for an empty object to be a valid type for T. This can cause problems as shown below:

To rectify this, modify your type C like so:

    type C<T extends A> = {
      b: Required<T>;
    }

With this change, you will be able to successfully implement it by doing:

    let c: C<{}> = {
      b: {},
    }

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