Tips for avoiding Union types in TypeScript from anticipating unnecessary keys?

My function getRespectiveConfig() returns a Union type that includes all the necessary types:

interface AlphaConfig {
    title: string;
}

interface BetaConfig {
    id: string;
}

export interface EncompassingConfig {
    alphaConfig?: AlphaConfig;
    betaConfig?: BetaConfig;
}

type ValueOf<T> = T[keyof T];
type RespectiveConfig = ValueOf<EncompassingConfig>; // *I may need to change this

export const getRespectiveConfig = (
    nodes: Node[] | undefined,
): RespectiveConfig | undefined => {
    return determineAndReturnRespectiveConfigType(nodes); // Assuming this returns AlphaConfig or BetaConfig
};

Explanation on how Modal below receives the prop currentlyEditingConfig:

interface Props {
    currentlyEditingConfig: BetaConfig | undefined;
}

Here is how the issue arises. currentlyEditingConfig expects to receive BetaConfig which is one of the possible types in RespectiveConfig. The error "Property 'id' is missing in type 'AlphaConfig' but required in type 'BetaConfig'." occurs:

<Modal
    currentlyEditingConfig={state.nodes ? getRespectiveConfig(state.nodes) : undefined}
/>

I suspect the issue lies in the first code block where I have marked *, I have attempted to use variations of Pick<K, T> but have been unsuccessful in resolving it.

Useful threads:

  • Turn typescript interface property types into union
  • How to pass optional parameters while enforcing one to be passed in TypeScript?

Answer №1

This is my approach to solving the issue at hand - I found a workaround by altering the way Modal is called with the currentlyEditingConfig prop:

<Modal
    currentlyEditingConfig={
        state.nodes 
          ? (getRespectiveConfig(state.nodes) as BetaConfig) 
          : undefined
    }
/>

If you have a more elegant solution, please share it with me. Thank you!

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