Tips for Comparing and Extracting Values from Two Arrays of Objects

Question

Tips for Comparing and Extracting Values from Two Arrays of Objects

There are two sets of objects that I need to work with:

First set of objects ---->

[{locationId: 1, locationName: "Bangalore"}, {locationId: 2, locationName: "Mumbai"}]

Second set of objects ----->

[{baseId: 1, baseUnit: "abc"}, {baseId: 2, baseUnit: ""}]

Is there a more efficient method in Angular 6 to extract the locationName from the first set of objects based on the baseId from the second set of objects, and then push this information into a new set of objects without using a traditional for loop?

javascript angular typescript

Answer 1

Answer №1

Check out the code snippet below for a solution to your problem (with explanatory comments included):

// Iterating through the first array
const newArray = array1.map(location => {
    // Finding the corresponding object in the second array based on IDs
    const foundBase = array2.find(base => base.baseId === location.locationId);
    // If the object is found, merge the two objects and return
    if(foundBase){
        return Object.assign(location, foundBase);
    }
});

Answer 2

Check out the code snippet below for a solution to your problem (with explanatory comments included):

// Iterating through the first array
const newArray = array1.map(location => {
    // Finding the corresponding object in the second array based on IDs
    const foundBase = array2.find(base => base.baseId === location.locationId);
    // If the object is found, merge the two objects and return
    if(foundBase){
        return Object.assign(location, foundBase);
    }
});

Answer 3

Answer №2

const locations = [{locationId:1,locationName:"Bangalore"},{locationId:2, locationName:"Mumbai"}];
    const bases = [{baseId:1,baseUnit:"abc"},{baseId:2,baseUnit:""}]
    const result = [];

locations.map(location => {
  bases.map(base => {
    if (location.locationId == base.baseId) {
      result.push({
        "locationName": location.locationName,
        "baseUnit": base.baseUnit
      });
    }
  });
});


console.log(result);

Answer 4

const locations = [{locationId:1,locationName:"Bangalore"},{locationId:2, locationName:"Mumbai"}];
    const bases = [{baseId:1,baseUnit:"abc"},{baseId:2,baseUnit:""}]
    const result = [];

locations.map(location => {
  bases.map(base => {
    if (location.locationId == base.baseId) {
      result.push({
        "locationName": location.locationName,
        "baseUnit": base.baseUnit
      });
    }
  });
});


console.log(result);

Answer 5

Answer №3

Optimize your arrays with reduce method

In this example, we showcase the power of using the .reduce function on an array to streamline operations and create a new array:

let locations = [{id:1,name:"Bangalore"},{id:2, name:"Mumbai"}]
let units = [{id:1,unit:"abc"},{id:2,unit:""}]

// Merge objects from both arrays
locations.reduce((finalArray, _, index) => finalArray.concat({...locations[index], ...units[index]}), [])

Answer 6

Optimize your arrays with reduce method

In this example, we showcase the power of using the .reduce function on an array to streamline operations and create a new array:

let locations = [{id:1,name:"Bangalore"},{id:2, name:"Mumbai"}]
let units = [{id:1,unit:"abc"},{id:2,unit:""}]

// Merge objects from both arrays
locations.reduce((finalArray, _, index) => finalArray.concat({...locations[index], ...units[index]}), [])

Tips for Comparing and Extracting Values from Two Arrays of Objects

Answer №1

Answer №2

Answer №3

Optimize your arrays with reduce method

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