It seems like I might be overlooking something, but is it possible to define a function with just one existing type?
type Fn = (x: number) => boolean // this cannot be changed
const arrowFn: Fn = (x) => {
return !x
}
// Is there a way to achieve this?
function normalFn: Fn (x) {
return !x
}
Utilizing the Function keyword with const is also possible:
const normalFn: Fn = function (x) {
return !x;
};
However, a left-hand side is required to assign a type, whether it be a variable, constant, class method (and annotate), etc.
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