Tips for creating an interface in TypeScript with multiple properties of a specific type

I am looking to create an interface that can have properties of the same type, regardless of the content. For example:

type Reducer<S, P> = (state: S, payload: P) => S

interface Reducers {
  [name: string]: Reducer
}

This is how I am trying to implement it:

interface MyState {
  foo?: string
  bar?: string
}

const reducers: Reducers = {
  r1: (state: MyState, payload: string) => {
    return {foo: payload}
  }
}

Unfortunately, I am getting a compilation error. The error message is:

Error TS2314: Generic type 'Reducer' requires 2 type argument(s).

Can someone please advise me on what I am doing incorrectly?

Answer №1

Make sure to pass your generic arguments to the Reducers interface:

interface Reducers<S, P> {
  [name: string]: Reducer<S, P>
}

const reducers: Reducers<MyState, string> = {
  r1: (state: MyState, payload: string) => {
    return {foo: payload}
  }
}

If your compiler doesn't allow you to define the Reducer method inline (I've encountered this issue before), you can define the function externally:

const r1Reducer: Reducer<MyState, string> = (state: MyState, payload: string) => {
    return {foo: payload}
}

const reducers: Reducers<MyState, string> = {
  r1: r1Reducer;
}

Answer №2

Your code lacks explicit generic type declarations, causing an issue with determining the correct types for S and P.

type Reducer<S, P> = (state: S, payload: P) => S

interface Reducers<S, P> {
  [name: string]: Reducer<S, P>
}

interface MyState {
  foo?: string
  bar?: string
}

const reducers: Reducers<MyState, string> = {
  r1: (state: MyState, payload: string) => {
    return { foo: payload }
  }
}

Adding these generics type notations will help the compiler to correctly infer the types of S and P.

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