I have a scenario where an async function is declared with a return type as follows:
async function getNumber() {
const {number} = await API_getNumber();
return number;
}
export type Return = ReturnType<typeof getNumber>
In this case, Return is Promise<number>. Now, I need to use this return type but extract only the number part without the promise. Is it possible to achieve this?
Two approaches:
function generatePromise() {
return Promise.resolve(1)
}
const resultPromise = generatePromise()
type ResolveType<T> = T extends Promise<infer U> ? U : T
type PromiseResultType = ResolveType<typeof resultPromise> // => number
Second method:
function generatePromise() {
return Promise.resolve(1)
}
type ResolveType<T> = T extends Promise<infer U> ? U :
T extends (...args: any[]) => Promise<infer U> ? U :
T
type PromiseResultType = ResolveType<typeof generatePromise> // => number
Reference: How to Get the Underlying Type of a Promise
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