Tips for implementing an 'exclude' feature in TypeScript without encountering any error notifications

export function omit<T, U extends keyof T>(obj: T, keys: U[]): Omit<T, U> {
  return Object.keys(obj).reduce(  
    (acc, curr) => (keys.includes(curr as U) ? acc : { ...acc, [curr]: obj[curr] }),
    {}
  ) as Omit<T, U>;
}

Encountering an error with message

TS7053: Element implicitly has an 'any' type because expression of type 'any' can't be used to index type 'unknown'.

The goal is to eliminate all error messages and ensure the function is correctly typed.

Answer №1

It appears that you are attempting to retrieve an object, so I would suggest using Omit<T, U> instead of Exclude<T, U>:

To better understand the distinction, you can view it here

Below is a solution to prevent any errors:

export const omit = <T, U extends keyof T>(obj: T, keys: U[]): Omit<T, U> =>
  (Object.keys(obj) as U[]).reduce(
    (acc, curr) => (keys.includes(curr) ? acc : { ...acc, [curr]: obj[curr] }),
    {} as Omit<T, U>
  );

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