Tips for incorporating Extract<T, U> with a nested variant?

I've encountered an issue with generated types. A particular API is providing me with two types, and I want to create distinct aliases for each.

In TypeScript, we can utilize Extract<> to assist with this:

type Add = {
    type: 'add';
    id: string;
}
  
type Remove = {
    type: 'remove';
    id: string;
}
  
type Action = Add | Remove;

type addType = Extract<Action, {type: 'add'}>;
    // ^? Add

However, the way my variations are defined differs:

type ActionsCombined = {
    type: 'add' | 'remove';
    id: string;
}

type addTypeCombined = Extract<ActionsCombined, {type: 'add'}>;
    // ^? never

Although they appear equivalent to me, TypeScript doesn't recognize them as such. Is there a method to extract the add variant from ActionsCombined?

TS Playground

Alternatively, is there a way to transform the nested variant representation into two independent variants?

Answer №1

One potential solution is to transform the combined actions type into a generic form:

type CombinedActions<T extends 'add' | 'remove'> = {
    type: T;
    id: string;
}

type BlankAction = CombinedActions; // ERROR: Generic type 'CombinedActions' requires 1 type argument(s)
type AddAction = CombinedActions<'add'>; // type AddAction = { type: "add"; id: string; }
type RemoveAction = CombinedActions<'remove'>; // type AddAction = { type: "remove"; id: string; }
type TypoRemoveAction = CombinedActions<'remive'>; // ERROR: Type '"remive"' does not satisfy the constraint '"add" | "remove"'.

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