Tips for minimizing disagreements while implementing optional generic kind in TypeScript?

An issue arises in StateFunction due to its optional second generic type that defaults to a value. Even when omitting this second generic, undefined still needs to be passed as an argument, which contradicts the idea of it being optional.

While making args truly optional by using args? helps, it creates the need to check for null values even though the type is not nullable.

The option of overloading the function exists, but given the length of the actual function, this solution may not be optimal.

Is there a proper way to eliminate the need for passing the argument when the second generic type is left unspecified?

interface StateFunctionAction<T, P> {
  (saved: T, args: P): void
}

const StateFunction = <T, P = undefined>(value : T, action: StateFunctionAction<T, P>) => {
  let saved = value;
  return (args : P) => action(saved, args);
}

const example1 = StateFunction<string>("Hello World", (saved) => console.log(saved))
example1(); // Help -> An argument for 'args' was not provided.

const example2 = StateFunction<string, number>("Hello World", (saved, n) => console.log(saved + " " + n))
example2(5);

Answer №1

One option to consider is using void instead of undefined as the default generic type. This adjustment will cause the argument to be hidden.

const StateFunction = <T, P = void>(value : T, action: StateFunctionAction<T, P>) => {
  let saved = value;
  return (args : P) => action(saved, args);
}

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