Tips for obtaining the "inner type" of a particular "instance" in TypeScript's generics

Unable to find more appropriate language to elaborate beyond the title, I'm going to rely on the code itself:

let var1 = someExternalLibraryMethod(); // assume var1 is implicitly Promise<string>

let var2: typeof var1; // this approach enables me to "link" the types of both variables without explicitly defining them as the same type (e.g. let var2: Promise<string>;)

let var3: ???????; //I aim to align this type with the "inner" type of var1 without specifying it directly (e.g. instead of let var3: string;)

The selection of Promise<string> was random. I am seeking a method that can be applied to other instances of generic types, such as rxjs.Observable<number> and

mongoose.Schema<{_id: number}>
.

This methodology should function without the need for hardcoding the "outer" type. In other words, the term 'Promise' should not be explicitly mentioned. If TypeScript indeed supports this capability, my assumption is that the syntax might resemble something like

let var3: InnerTypes<typeof var1>[0]; // This is a speculative attempt and may not actually work

TypeScript version: 3.x

Answer №1

To implement conditional types, you can follow this general approach:

type Data = ReturnType<typeof someSpecificFunction>; // Promise<string>
type Result = Data extends Promise<infer R> ? R : never;

The crucial concept here is the ability to infer the inner type within the extends clause.

Interactive Example

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