Tips on creating a union of tuple types in a way that maintains the association of variable types even after destructuring

Is it possible to specify the data types of tuples in a way that allows for type inference as illustrated in the comments within the code snippet below?

declare const tuples: [number, null] | [null, number];

const [a, b] = tuples;

const fun = () => {
  if (a === null) {
    const c = b; // Can we define the type of 'tuples' so that 'c' is inferred as 'number'???

    return;
  }

  const d = b; // How can we specify the type of 'tuples' so that 'd' infers as 'null'???
}

Answer №1

It's important to avoid destructuring the array until you have identified its type.

Destructuring before determining the specific array type can lead to a disconnection between elements and their corresponding types. For instance, with the initial type of [number, null] | [null, number], accessing elements without confirming the array type first will result in TypeScript assigning a generic type like number | null. This causes TypeScript to analyze variables independently, which can lead to unexpected behavior.

The solution is to delay destructuring until after verifying the array type:

declare const tuples: [number, null] | [null, number];

const fun = () => {
  if (tuple[0] === null) {
    const [a, b] = tuples
    const c = b; // c has type number

    return;
  }

  const [a, b] = tuples
  const d = b; // d has type null
}

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