Tips on "populating" generic parameter in typescript

Imagine I have a generic TypeScript function that looks like this:

function performAction<X>(input: X): X {
    //...
}

Now, let's consider a specific interface called YourType:

interface YourType {
    a: string;
    b: number;
}

I aim to export the performAction method with the assumption that the generic parameter X will always be YourType. This way, when I type something like:

performAction({

...the editor will automatically suggest completion for properties a and b, eliminating the need for me to specify X beforehand.

One approach is to:

import {performAction as _performAction} from 'some-package';
export const performAction = _performAction as (input: YourType) => YourType;

However, this method is tedious and prone to errors. Moreover, the actual performAction has more elements and variations than shown in this simplified illustration, which would require extensive copying and pasting.

Is there a simpler way to "fill in" X without duplicating the entire original definition?

Answer №1

Since the introduction of TypeScript 4.7, this code has been permitted.

const foo: typeof doThing<MyType> = doThing

Update: Although it was supposed to work according to the release notes, due to a bug, additional parentheses are now required for line (2) in TypeScript 4.8.

const foo = doThing<MyType>    // (1) error
const foo = (doThing)<MyType>  // (2) ok

Answer №2

One possible approach is to utilize the function in the following manner:

const result = performAction<MyCustomType>({a: "example", b: 123});

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